Why Pointers are Eliminated in Java?

 This is rare question but it is good to get prepared with such type of Questions as it may be asked in Beginner level.

  • The first motivation is to make Java programming less complicated. Java is an easy-to-learn, object-oriented programming language. As is well known, the pointer idea is very confusing, challenging to understand (especially for beginners), and leads to coding errors. 

  • The pointers concept was eliminated by the designers of Java in order to make it less complicated and more straightforward.

  • Memory can be allocated and deallocated via pointers. Although this is a useful aspect of pointers, manually managing memory can occasionally be challenging for programmers. Pointers are not required because Java has an automatic garbage collection mechanism, which simplifies memory management.

  • One of the major problems in the field of programming is security. Direct access to a memory address is provided through a pointer. As a result, it is simple to access any memory region and perform read and write operations on it.
  • This can lead to a security breach. In order to make Java secure, pointers are not supported. Java has a secure and strong feature set.



Comments

Post a Comment

Popular posts from this blog

Integer.parseInt(“text”)

Image
  What will happen if we execute the program int a = Integer.parseInt(“text”) ? class HelloWorld { public static void main(String[] args) { int a = Integer.parseInt(“text”); System.out.print(a); } } When this program is executed this will throw the following Exception Exception in thread "main" java.lang.NumberFormatException: For input string: "text"at java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)at java.base/java.lang.Integer.parseInt(Integer.java:652)at java.base/java.lang.Integer.parseInt(Integer.java:770) at HelloWorld.main(HelloWorld.java:7) This is because parseInt() is used to get the primitive data type of the given string. It need to accepts the Integer in the form of String. But here we have given "text" as an Input in place of Integer. So it has thrown Number for Exception. It can be corrected by giving any Integer as an Input. class HelloWorld { public static void main(String...
Read more

What is the advancement made in Hashmap in Java 8?

Image
We'll talk about an intriguing update on HashMap performance Improvement Changes in Java 8. Due to a performance issue, the Oracle changed HashMap.  What is HashMap and How it is Implemented? It keeps the key-value pair in storage where it may be retrieved with the use of a key. You must be familiar with how HashMap is Implemented only then we can understand what was the performance issue we had earlier and how that has been overcome by Oracle in Java 8. As its name suggests, HashMap operates on the concept of hashing. Equals() and hashcode() are two of the methods included in the Java Object class. We need to appropriately override these methods in order to get our HashMap to behave as expected. Any problems with these approaches could even invalidate the entire purpose since there is a chance that the results won't be retrieved even if the key-value pair is still there. HashMap use the Basic Implementation of Map Interface. When there is a hash collision, the entry's Link...
Read more